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Datediff question. (2)
- Subject: Datediff question. (2)
- From: Romeu Sciotta <tb09@PETROBRAS.COM.BR>
- Date: Wed, 18 Nov 1998 08:55:21 -0300
From: NAME: Romeu Finoti Sciotta
FUNC: DTSE/SUPER/DITEP/SETEC <TB09@A1@C60000>
To: NAME: SMTP%"SQR-USERS@usa.net" <SMTP%"SQR-USERS@usa.net"@C6000G@C6000G@MRGATE@C60000>
Hi Raj,
datediff is a SQR function only in version 4.
Anthony,
I tried to use an alphanumeric variable and it didn't work.
Thank you for your tips.
If anyone have a new tip, I'll be grateful.
Romeu F. Sciotta
MIPS Sistemas (PSDI var in Brazil)
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>From: "Singh, Rajvirendra NY ESA" <RajvirendraSingh@EXCHANGE.ML.COM>
>Subject: Re: Datediff question.
>X-To: "SQR-USERS@USA.NET" <SQR-USERS@USA.NET>
>To: Multiple recipients of list SQR-USERS <SQR-USERS@list.iex.net>
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>
>Hi Romeu,
>
>Datediff is SQR function not a database function. You can use it in your
>LET, IF, WHILE command. You can not this function as part of select
column
>list.
>
>Raj
>
> -----Original Message-----
> From: Romeu Sciotta [SMTP:tb09@PETROBRAS.COM.BR]
> Sent: Tuesday, November 17, 1998 2:25 PM
> To: Multiple recipients of list SQR-USERS
> Subject: Datediff question.
>
> From: NAME: Romeu Finoti Sciotta
> FUNC: DTSE/SUPER/DITEP/SETEC <TB09@A1@C60000>
> To: NAME: SQR UserGroup <SMTP%"SQR-USERS@usa.net"@mrgate>
>
> Hello to all.
>
> When I try to put a variable into datediff command on
begin-select
> paragraph, I receive the following message:
>
> (SQR 1303) Error in SQL (perhaps missing &name after expression):
> select DATEDIFF(day, WO.REPORTDATE, ?) From WORKORDER WO Where
>WO.WONUM =
> '15485'
> (SQR 1304) Check SELECT columns, expressions and 'where' clause
for
> syntax.
>
> Where is "?" I'm using a variable (ex: &dateinit)
> My question is: Doesn't SQR support variables into DATEDIFF
command?
> Obs.: I've tried to use this command directly on SQL and it
worked.
>
> Any help would be appreciate.
> Thank's in advance.
>
> Romeu F. Sciotta
> MIPS Sistemas (PSDI var in Brazil)
>
> Inf: SQR v3 for ODBC