Re: '#if' question

[Juergen Stienecke <stien@DICAD.DE>]

Hi Angel,

sqr is compiling the code.
So it compiles if #which_array ...
In this statement array $2array-name is used bur not (!) defined.
So there is a compilation error.

Comment out this part of code.

Juergen Stienecke
stien@dicad.de
DICAD Software GmbH, Cologne


>What's wrong with my code?
>I get error SQR 4707,
>No value found for substitution variable: {$2array-name}
>variable #which_array is set to 1...
>
>
>#define $1array-name  dparray
>!#define $2array-name  wcarray
>!i commented out above line because this array does not exist
>! for this program but it does for another program.
>...
>...
>...
>        if #which_array=1
>            #if {$1array-name}='dparray'
>               put $something into dparray(#record)
>            #end-if
>            #if {$1array-name}='jcnarray'
>               put $something into jcnarray(#record)
>               let $something = 'nothing'
>               get $something from jcnarray(#record)
>               show 'after display = ' #record ' ' $something
>            #end-if
>        end-if
>
>        if #which_array=2
>!error is on this line
>            #if {$2array-name}='wcarray'
>               put $something into wcarray(#record)
>            #end-if
>        end-if
>
>