RE: [sqr-users] passing parameters to sqr..

["the dragon" <ceprn@hotmail.com>]

You're going to have to think harder to receive the telepathic images he is 
sending...

Don't you know us gurus can solve the problems of the planet with just a 
couple of lines of information?

peace,
clark 'the dragon' willis



PSA: Salary <> Slavery. If you earn a salary, your employer is renting your 
services for 40 hours a week, not purchasing your soul. Your time is the 
only real finite asset that you have, and once used it can never be 
recovered, so don't waste it by giving it away.

I work to live; I don't live to work.

"Time is the coin of your life. It is the only coin you have, and only you 
can determine how it will be spent. Be careful lest you let other people 
spend it for you." -- Carl Sandburg (1878 - 1967)

It is impossible to defeat an ignorant man in argument. -- William G. McAdoo

Religion is regarded by the common people as true, by the wise as false, and 
by the rulers as useful. -- Seneca

"I distrust those people who know so well what God wants them to do because 
I notice it always coincides with their own desires." - Susan B. Anthony




----Original Message Follows----

And the error message would be?

-----Original Message-----

Hi

   Iam getting error when i use the following shell script

sqr /t111/app01/psoft/usdx/usr/sqr/parallel.sqr -RT uid/pwd@ORACLE_SID  
-i/t111/app01/psoft/usdx/sqr/
-ZIF/t111/app01/psoft/usdx/sqr/pssqr.unx 1

Iam calling sqr called parallel.sqr thru shell program. last parameter in 
the above syntax is "1" that i want to pass to the sqr.
pls help

Thanks
Ram

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