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RE: [sqr-users] how to remove a single quote from a name
- Subject: RE: [sqr-users] how to remove a single quote from a name
- From: "Alexander, Steven" <Steven.Alexander@sanjoseca.gov>
- Date: Mon, 23 Oct 2006 13:41:55 -0700
- Delivery-date: Fri, 27 Oct 2006 16:44:50 -0400
- List-id: "This list is for discussion about the SQR database reportinglanguage from Hyperion Solutions." <sqr-users.sqrug.org>
A single quote is '''' - the first quote to start the string, the second
quote to be a quote, the third quote to say you really mean it, and the
fourth quote to end the string. So, if you wanted to have a literal value
in your program for O'Hara, you would type 'O''Hara'.
-----Original Message-----
From: sqr-users-bounces+steven.alexander=sanjoseca.gov@sqrug.org
[mailto:sqr-users-bounces+steven.alexander=sanjoseca.gov@sqrug.org] On
Behalf Of Overcashier, Patricia
Sent: Tuesday, October 17, 2006 9:30 AM
To: This list is for discussion about the SQR database reportinglanguage
fromHyperion Solutions.
Subject: [sqr-users] how to remove a single quote from a name
Hi everyone,
I select a last name and before comparing it I remove all special
characters.
Thanks to all of your help, I can do that successfully.
The only character that I seem to struggle with removing is the single quote
I have the name O'Hara
I want it to be OHara
I am using translate to remove all of the other oddities.
let $lname = translate(lower($lname),'абвзийксуцн','aaaceeenooi')
I have tried this:
find ''' in $lname 0 #pos My errors happen here. I can't find the
single quote to get rid of it.
if #pos > 0
let #pso2 = #pos + 1
let $newlname = substr(lname,0,#pos)||substr($lname,#pos2)
end-if
Thanks again,
Patti Overcashier
Information Technology - PeopleSoft
American Axle & Manufacturing, Inc.
Detroit Gear Plant 3
1840 Holbrook
Detroit, MI 48212
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