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Re: [sqr-users] How can I tell which SQC is causing the error?
If you're on unix/linux you could do something like...
grep -n '!=' *.sqc |grep ':1105:'
That would be the easiest way.
HTH,
Don
john.tucker@oracle.com wrote:
> I'm looking at an error log for an SQR that I just finished writing, and it
>reminded me of a question that I've often had, but have never found an answer
>to. Partly, that's just because I'm not sure how to ask Google...
>
> My error log says:
>
> Error on line 2796:
> (SQR 5102) Out of Break commands; Use -Mfile to increase BREAKS.
>
> Error on line 1105:
> (SQR 4048) Function or operator '!=' must be a string or date argument.
>
>
> I know where the first error is coming from, and how to solve it, but I don't
>know where the second error is coming from. I didn't use != in any of the
>code I wrote, so I'm assuming at this point that it comes from an SQC that I'm
>including but didn't write personally (I'm working with an Oracle database on
>a PeopleSoft implementation).
>
> So my question to you all is this: is there a way to find out which sqc has
>the line 1105 that's having an SQR 4048 error?
>
> -John T.
>
>
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> http://www.sqrug.org/mailman/listinfo/sqr-users
>
>
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Donald Mellen | Ray Ontko & Co. - Richmond, IN - http://www.ontko.com/
donm@ontko.com | "In the beginning, there was nothing, which exploded"
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