RE: [sqr-users] Running a SQR program from another SQR program

["tam kag" <kaghdot@hotmail.com>]

the error code is the code returned from CALL SYSTEM USING $cmd_ln 
#return_status.

#return_status is equal to 6, I couldn't find out what error code 6 means



>From: "Knapp, Richard" <KnappR@umsystem.edu>
>Reply-To: "This list is for discussion about the SQR database 
>reportinglanguage from Hyperion Solutions." <sqr-users@sqrug.org>
>To: "This list is for discussion about the SQR database reportinglanguage 
>fromHyperion Solutions." <sqr-users@sqrug.org>
>Subject: RE: [sqr-users] Running a SQR program from another SQR program
>Date: Tue, 19 Jul 2005 12:05:55 -0500
>
>
>Is there any text with the error code?  Is it SQR or the operating
>system that is originating the error?
>
>Richard Knapp
>Database Programmer/Analyst
>Institutional Research and Planning
>University of Missouri System
>573-882-8856
>knappr@umsystem.edu
>
>-----Original Message-----
>From: sqr-users-bounces+knappr=umsystem.edu@sqrug.org
>[mailto:sqr-users-bounces+knappr=umsystem.edu@sqrug.org] On Behalf Of
>tam kag
>Sent: Tuesday, July 19, 2005 11:47 AM
>To: sqr-users@sqrug.org
>Subject: [sqr-users] Running a SQR program from another SQR program
>
>Hello,
>Within my SQR(program A), I'm trying to execute another SQR(program B)
>by
>building a string variable and using the CALL SYSTEM command.
>
>I have tested my command by typing it manually and running it in our AIX
>
>box, the command ran successfully, but when I copy the same command an
>paste
>it in program A  it is returning an error code 6.
>
>any info is most appreciated
>
>Thanks
>
>
>
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