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RE: [sqr-users] date format
- Subject: RE: [sqr-users] date format
- From: "Jon Alsager" <Jalsager@ISIF.STATE.ID.US>
- Date: Tue, 10 May 2005 09:15:01 -0600
- Delivery-date: Tue, 10 May 2005 10:21:39 -0500
- List-id: "This list is for discussion about the SQR database reportinglanguage from Hyperion Solutions." <sqr-users.sqrug.org>
- Thread-index: AcVVcqRq0iGcRKDsSrepFZpgDolHvQAADLsA
- Thread-topic: [sqr-users] date format
Maybe try this:
let $activity_date = strtodate($activity_date, 'YYYYMMDD')
Jon
-----Original Message-----
From: sqr-users-bounces+jalsager=isif.state.id.us@sqrug.org
[mailto:sqr-users-bounces+jalsager=isif.state.id.us@sqrug.org] On Behalf
Of radhika reddy
Sent: Tuesday, May 10, 2005 9:02 AM
To: sqr-users@sqrug.org
Subject: [sqr-users] date format
Hi,
I always have tough time to format dates. This time the date that I
get
from a flat file is in 'YYYYMMDD' format. However i do it i get errors.
I tried doing something like this:-
Let $activity_date = edit($activity_date, 'dd-mon-yyyy')
or
let $activity_date = to_char(to_date($activity_date, 'YYYYMMDD'),
'dd-MON-yyyy')
and
let $activity_date =
Datetostr(StrtoDate($activity_date,'YYYYMMDD'),'dd-MON-yyyy')
and
begin-select on-error=print-date-error
to_char(to_date($activity_date, 'MM/DD/YYYY'), 'dd-MON-yyyy')
&activitydate
move &activitydate to $activity_date
from dual
Any idea where i am going wrong on this?
Thanks.
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