Re: [sqr-users] problems with using length(field)

["Joe Johnson" <jej1216@hotmail.com>]

Thanks to all for your help - it lead me to the correct approach.

I changed the code to the following so that I was working with the numeric 
length, and the code now is correct:

==================================================

begin-SELECT
ET.DESCR
ET.GL_EXPENSE

   let $Erncd_Descr      = rtrim(&ET.DESCR,' ')
   let $GL_Expense       = rtrim(&ET.GL_EXPENSE,' ')
   let #GL_Expense_Lngth = length(rtrim(&ET.GL_Expense, ' '))

     evaluate #GL_Expense_Lngth
       when = 12
       when > 12
         show 'length 12+'
         if substr($GL_Expense,1,3) = '900'
            let $Acct_Cd = substr($GL_Expense,7,6)
            let $DeptID  = '0000'
         end-if
         if substr($GL_Expense,1,2) = '10'
            let $DeptID  = substr($GL_Expense,3,4)
            let $Acct_Cd = substr($GL_Expense,7,6)
         end-if
         if substr($GL_Expense,1,2) = '08'
            let $DeptID  = substr($GL_Expense,3,4)
            let $Acct_Cd = substr($GL_Expense,7,6)
         end-if
         if substr($GL_Expense,1,3) = '000     '
            let $Acct_Cd = substr($GL_Expense,7,6)
            let $DeptID  = '0000'
         end-if
       break
       when = 6
            show 'length 6'
            let $Acct_Cd = substr($GL_Expense,1,6)
       break
     end-evaluate

from
   PS_EARNINGS_TBL ET

where
   ET.ERNCD = $Erncd
  and ET.EFF_STATUS = 'A'
  and ET.EFFDT =
    (select max(ET1.EFFDT)
     from PS_EARNINGS_TBL ET1
     where ET.ERNCD       = ET1.ERNCD
       and ET1.EFF_STATUS = 'A'
       and ET1.EFFDT     <= $AsOfToday)

group by ET.DESCR, ET.GL_EXPENSE

end-SELECT

==========================================

- Joe

----Original Message Follows----
From: Don Mellen <donm@ontko.com>
Reply-To: "This list is for discussion about the SQR database 
reportinglanguage from Hyperion Solutions." <sqr-users@sqrug.org>
To: "This list is for discussion about the SQR database reporting 
languagefrom Hyperion Solutions." <sqr-users@sqrug.org>
Subject: Re: [sqr-users] problems with using length(field)
Date: Mon, 28 Feb 2005 17:25:11 -0500 (EST)
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FILETIME=[D09BFD40:01C51DE4]

The logic works perfectly, but you have to realize that you're doing
string comparison, not number comparison.

Try something like...

SELECT
ET.DESCR
ET.GL_EXPENSE
LENGTH(ET.GL_EXPENSE) &ET.GL_EXPENSE_LNGTH=number
FROM TABLE ET

... and ...

   evaluate &ET.GL_EXPENSE_LNGTH
     when >= 12
       show 'Length 12+'
       break
     when = 6
       show 'Length 6'
       break

    ... etc

HTH,
Don


On Mon, 28 Feb 2005, Joe Johnson wrote:

 > I have a requirment to process data according to the length of one field.
 >
 > I am getting the length this way:
 >
 > SELECT
 > ET.DESCR
 > ET.GL_EXPENSE
 > LENGTH(ET.GL_EXPENSE) &ET.GL_EXPENSE_LNGTH
 > FROM TABLE ET
 >
 > The result of &ET.GL_EXPENSE_LNGTH is then pared down to:
 >
 >    let $GL_Expense_Lngth = &ET.GL_EXPENSE_LNGTH
 >    let $GL_Expense_Lngth = rtrim($GL_Expense_Lngth, '0')
 >    let $GL_Expense_Lngth = rtrim($GL_Expense_Lngth, '.')
 >
 > which changes "6.0000000000000000000000" to "6"
 >
 > I have show statements to verify that $GL_Expense_Lngth is identifying 
the
 > correct length.
 >
 > However, when I try to apply some of the programming logic according to
 > length, the logic fails.  The code:
 >      evaluate $GL_Expense_Lngth
 >        when = '12'
 >        when > '12'
 >          show 'Length 12+'
 >        break
 >        when = '6'
 >          show 'Length 6'
 >        break
 >        when = '0'
 >          show 'Length 0'
 >        break
 >      end-evaluate
 >
 > There are two problems:
 >
 > 1) when the field is blank, it's being shows as $GL_Expense_Lngth=1
 >
 > 2) when the field is 6, it's applying the logic for $GL_Expense_Lngth => 
12
 >
 > Any help would be appreciated.
 >
 > Thanks,
 >
 > Joe Johnson
 >
 > ~ JEJ ;{) ~
 >
 >
 >
 > _______________________________________________
 > sqr-users mailing list
 > sqr-users@sqrug.org
 > http://www.sqrug.org/mailman/listinfo/sqr-users
 >

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Donald Mellen  | Ray Ontko & Co. - Richmond, IN - http://www.ontko.com/
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