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RE: [sqr-users] On Break Option
- Subject: RE: [sqr-users] On Break Option
- From: "the dragon" <ceprn@hotmail.com>
- Date: Wed, 26 May 2004 06:48:32 -0500
- Bcc:
- Delivery-date: Wed, 26 May 2004 06:50:00 -0500
- List-id: "This list is for discussion about the SQR database reportinglanguage from Hyperion Solutions." <sqr-users.sqrug.org>
post the program
PSA: Salary <> Slavery. If you earn a salary, your employer is renting your
services for 40 hours a week, not purchasing your soul. Your time is the
only real finite asset that you have, and once used it can never be
recovered, so don't waste it by giving it away.
"Time is the coin of your life. It is the only coin you have, and only you
can determine how it will be spent. Be careful lest you let other people
spend it for you."
Carl Sandburg
(1878 - 1967)
----Original Message Follows----
Hi all,
I am getting following data.
Custname
--------------
cust1
cust1
cust1
cust2
cust2
Now I want to show it like
Custname
--------------
cust1
cust1
cust1
Cust name: cust1 : 3
cust2
cust2
Cust name: cust2 : 2
I am using this command.
crmserv.srno &service_req_id
crmserv.srdesc &service_req_subject_desc
crmserv.createdate &create_dt
crmserv.statuscd &service_req_status_cd
crmserv.topicdesc &service_req_topic_desc
crmserv.srreqtype &serv_req_typ
corp.description &cust_nam () on-break level=1 print=never
after=cust_count
crmserv.srowner &assigned_to_last_nam
corp.cnt &custcount
But I'm getting count in the begining instead of after cust name. My output
shows following
Custname
--------------
Cust name: cust1 : 3
cust1
cust1
cust1
Cust name: cust2 : 2
cust2
cust2
what could be the reason?
Thanks in advance...
Darshil
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