[sqr-users] on-break puzzler

["the dragon" <ceprn@hotmail.com>]

Guys (of any sex or gender),

I have some code in my program (see below).  In this code, the only columns 
that *ever* have a value are [$SUMCF1] , [$SUMCF2]  and [$SUMCF3].  So, my 
question is, how is the on-break logic on [$sum29] firing????

[$SUMCF1]   &SumCF1=char  () on-break LEVEL=1 PRINT=NEVER SAVE=$SAVECF1
[$SUMCF2]   &SumCF2=char  () on-break LEVEL=1 PRINT=NEVER SAVE=$SAVECF2
[$SUMCF3]   &SumCF3=char  () on-break LEVEL=1 PRINT=NEVER SAVE=$SAVECF3
etc.....
[$SUMCF26] &SumCF26=char () on-break LEVEL=1 PRINT=NEVER SAVE=$SAVECF26
[$SUMCF27] &SumCF27=char () on-break LEVEL=1 PRINT=NEVER SAVE=$SAVECF27
[$SUMCF28] &SumCF28=char () on-break LEVEL=1 PRINT=NEVER SAVE=$SAVECF28
[$SUMCF29] &SumCF29=char () on-break LEVEL=1 PRINT=NEVER after=ledger-break 
SAVE=$SAVECF29

I can see that the program enters the procedure lefger-break, yet nothing is 
changing in the column.

thanks in advance,

clark


PSA: Salary <> Slavery.  If you earn a salary, your employer is renting your 
services for 40 hours a week, not purchasing your soul.  Your time is the 
only real finite asset that you have, and once used it can never be 
recovered, so don't waste it by giving it away.

"Time is the coin of your life. It is the only coin you have, and only you 
can determine how it will be spent.  Be careful lest you let other people 
spend it for you."

Carl Sandburg
(1878 - 1967)

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