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RE: [sqr-users] help with next-listing command
- Subject: RE: [sqr-users] help with next-listing command
- From: Peter Burton <pburton@brio.com>
- Date: Thu, 12 Dec 2002 14:09:08 -0500
- List-id: This list is for discussion about the SQR database reporting language from Brio Software. <sqr-users.sqrug.org>
Dinesh,
Use NO-ADVANCE option
Peter
-----Original Message-----
From: Dinesh [mailto:dinesh@redwoodtoxicology.com]
Sent: Thursday, December 12, 2002 2:04 PM
To: sqr-users@sqrug.org
Subject: [sqr-users] help with next-listing command
Hi All,
I am wondering if you can help with this problem. What I am trying to do is
get the data from arrayand print it out without skipping any lines in
tabular format.
If I were to use next-listing command to print a list of records, the
records are shifted ( skip lines) according the line position. For example
if the line position equals to 1, it adds one line, and if the line position
equals to 30 it adds another 30. Is there a better way to print the list
from the array without skipping that many lines. Please let me know if you
know, I will be greally grateful!!!
thank you
dinesh
Begin-Procedure procedure_one
#define line_position
#define column_position
let #array_count = 0
while (#array_count < #sql_count)
get $default_item_desc from default_item_desc(#array_count)
print $default_item_desc ({line_position}, {column_position}) point-size=8
next-listing skiplines=0
add 1 to #array_count
end-while
End-Procedure ! procedure_one
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