[Date Prev][Date Next][Thread Prev][Thread Next]
[Author Index] [Date Index] [Thread Index]
[SQR-USERS Info] [SQRUG Home Page]

Re: Calling sqr from an sqr in an Unix system

Here you go:

let $sqr_com = 'sqr igaudproc.sqr ' || $sysuser || '/' || $syspass
Call System Using $sqr_com #Status


----- Original Message -----
From: "Prasanna Menta" <pmenta@UMUC.EDU>
To: <SQR-USERS@list.iex.net>
Sent: Thursday, May 30, 2002 2:23 PM
Subject: Calling sqr from an sqr in an Unix system


> Does Anyone have an example to call an sqr within an sqr in an Unix
> system.
>