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Rép. :



Here comes a script-shell to compile sources.
See if it respond to your question...

Cordialement, Philippe.

>>> Soliman Heba Contr <Heba.Soliman@FSCNET.VANDENBERG.AF.MIL> 01/03/01 01h55 
>>>>
Hello,
I am using oracle database, UNIX, and SQR.  I need to compile SQR files.
Are there any way to debug ?
Thanks,
Heba

VARIABLES=1500
PROGLINEPARS=30000
QUERYARGS=1000
QUERIES=500
STRINGSPACE=55000
PROGLINES=6000
SQLSIZE=16000
EXPRESSIONSPACE=65000

export SQRDIR=/soft/sqrv4.3.2.1/ora/bin
export SQR_FLAG=-RT
export REP_SQR=.

#! /bin/sh

if [ -n "$1" ]
then
        Fichier=$1
        shift
        Options=$@
else
        Fichier=""
        Options=""
fi

rm sqr2sqt.log

if [ -z "$Fichier" ]
then
        for Fichier in `ls *.sqr`
        do
                echo " \nCompilation SQR V4.3 : $Fichier"
                echo " \n\n\nCompilation SQR V4.3 : $Fichier" >> sqr2sqt.log
                ( ${SQRDIR}/sqr $Fichier cable/cable -Msqrparm.dat -rs 2>&1 )| 
tee -a sqr2sqt.log
                NomFic=`basename ${Fichier} .sqr`.sqt
        done
else
        echo " \nCompilation SQRV43 : $Fichier"
        echo " \n\n\nCompilation SQRV43 : $Fichier" >> sqr2sqt.log
        if [ -n "$Options" ]
        then
                echo "Options de compilation: $Options \n"
                echo "Options de compilation: $Options \n" >> sqr2sqt.log
        fi
        ( ${SQRDIR}/sqr $Fichier $Options cable/cable -Msqrparm.dat -rs 2>&1 )| 
tee -a sqr2sqt.log
        NomFic=`basename ${Fichier} .sqr`.sqt
        chmod 755 ${NomFic}
fi