RE: [sqr-users] Return Code

["Bencke, Gina" <gbencke@kichler.com>]

Mike,


SQR, by default always returns a 'success' value to the OS unless you
set #return-status to another value.  Even if you call the stop command,
SQR returns success. 

A technique I use in my SQR programs is in the beginning of the program
I set #return-status to 'bad' and at the end or the program to 'good'.
Then if the program either ends prematurely to an execution error or a
stop command the 'bad' value will be returned to the OS.  

#define GOOD-OS-STATUS 0 ! Well-behaved UNIX commands, programs, and
utilities return a 0 exit code upon successful 
#define BAD-OS-STATUS  1

Begin-program
  let #return-status = {BAD-OS-STATUS}
  ...
  let #return-status = {GOOD-OS-STATUS}
End-program 
  

 Gina Bencke
 Work 216-573-1005 X6805 | Mobile 440-479-9961 | Fax 216-573-1070
 Home Office 440-519-0060  
 

-----Original Message-----
From: sqr-users-bounces+gbencke=kichler.com@sqrug.org
[mailto:sqr-users-bounces+gbencke=kichler.com@sqrug.org] On Behalf Of
Moss, Mike 
Sent: Wednesday, January 16, 2008 1:14 PM
To: sqr-users@sqrug.org
Subject: [sqr-users] Return Code 

Hello,

I'd like to find out how to force and SQR to error on a certain
condition so that a Unix script which runs the SQR can recognize that
the SQR failed.  I read that #return-status is a reserved variable but I
don't know what to set #return-status to in order for it to indicate
that the SQR has failed.  I also saw the 'stop' command, but it wasn't
clear to me that if I used the stop command, that the SQR run status
would be set to error.  

Thanks.  
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