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RE: [sqr-users] COMPARE DATE



i'm not sure how you're getting date_compare to be an 8 digit number, but I
would think your date variable would be a string.  Lets assume its a static
string that you've set somewhere else (or you can set it up however you
want).  


let $compare_date = '2004-11-19 15:51:32'

begin-select 
to_char(sysdate,'YYYY-MM-DD HH24:MI:SS')   &date
   let $sysdate = &date
from dual
end-select

if $compare_date > $sysdate
  do subprocedure_a
end-if


The date edit-mask you use isn't important, just so it's the same throughout
the SQR (and it helps if it's the same through all SQRs).  You could use
'YYYY-MM-DD' without the time part.

to_char(sysdate,'YYYY-MM-DD HH24:MI:SS')  
to_date('2004-10-20 14:01:19', 'YYYY-MM-DD HH24:MI:SS')  <-- for comparisons
in DB.

Now, if you're saying that you start with a number (i dont know why your
date would be a number, but lets say it is) I might move the sysdate to a
$var with edit mask to get rid of all non-numeric parts of the date, then
move to a #nbr and compare.


let #compare_date = 20050101

begin-select
to_char(sysdate, 'YYYYMMDD)     &date
   let $sysdate = &date
   move $sysdate to #sysdate
from dual
end-select

if #compare_date > #sysdate
  do subprocedure_a
end-if.



-----Original Message-----
From: sqr-users-bounces+bstone=fastenal.com@sqrug.org
[mailto:sqr-users-bounces+bstone=fastenal.com@sqrug.org]On Behalf Of
Chuyen Do
Sent: Friday, November 19, 2004 3:34 PM
To: sqr-users@sqrug.org
Subject: [sqr-users] COMPARE DATE


Please HELP me the syntax:

#DATE_to_be_compared = 20041119

if #DATE_to_be_compared > sysdate !it means date at the time the
program    do ..                          ! is running.
end-if

I don't know the reserved name for sysdate

Thanks
Chuyen Do

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