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Re: [sqr-users] round
If you declare the #i variable to be an integer, it should work. Here is
some test code I ran:
!************************************
begin-setup
declare-variable
integer #num_value
end-declare
end-setup
begin-program
let #num_value = 8 / 7
show '8 / 7 = ' #num_value
let #num_value = 7 / 7
show '7 / 7 = ' #num_value
let #num_value = 6 / 7
show '6 / 7 = ' #num_value
end-program
!************************************
The results were:
8 / 7 = 1
7 / 7 = 1
6 / 7 = 0
SQR: End of Run.
"Ben Anderson"
<pegandersonbd1@h To: sqr-users@sqrug.org
otmail.com> cc:
Sent by: Subject: [sqr-users] round
sqr-users-admin@s
qrug.org
04/08/2003 10:57
AM
Please respond to
sqr-users
I want to either do integer divide or round:
let #i = 8/7 !I want this to be 1
let #i = 7/7 !I want this to be 1
let #i = 6/7 !I want this to be 0
I've been getting the decimal values and I want the integer. If I need to
put steps in between, that's fine.
Thanks,
Ben Anderson
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